Which coenzyme is not required in the formation of glutamate?
Which of the following is not a metabolic product of the urea cycle?
Which amino acid is not involved in transamination?
Boiled cabbage or rancid butter smelling urine is seen in
Apo B48 is synthesized in -
What is the end product of purine metabolism in most mammals?
Which of the following statements is true regarding the sigma factor?
What is a key similarity between the processes of replication and transcription?
What are Okazaki fragments?
What is the first purine nucleotide synthesized in de novo purine biosynthesis?
NEET-PG 2015 - Biochemistry NEET-PG Practice Questions and MCQs
Question 51: Which coenzyme is not required in the formation of glutamate?
- A. None of the above
- B. Pyridoxal phosphate
- C. Thiamine pyrophosphate (Correct Answer)
- D. Niacin
Explanation: ***Thiamine pyrophosphate*** - **Thiamine pyrophosphate (TPP)** is a coenzyme derived from **vitamin B1** that is essential for reactions involving decarboxylation, such as those catalyzed by pyruvate dehydrogenase and alpha-ketoglutarate dehydrogenase. - The formation of glutamate primarily involves transamination or reductive amination, which do not require TPP. *Pyridoxal phosphate* - **Pyridoxal phosphate (PLP)**, derived from **vitamin B6**, is a crucial coenzyme for **transamination reactions**, which are a major pathway for glutamate synthesis (e.g., from alpha-ketoglutarate). - It also plays a role in decarboxylation and deamination reactions of amino acids. *Niacin* - **Niacin (vitamin B3)** is a precursor for **NAD+** and **NADP+**, which are essential coenzymes in many metabolic pathways. - **NADPH**, derived from NADP+, is required as a reductant in the **reductive amination** of **alpha-ketoglutarate** to form glutamate, catalyzed by glutamate dehydrogenase. *None of the above* - This option is incorrect because **thiamine pyrophosphate** is indeed not required for the formation of glutamate. - The other two coenzymes, **pyridoxal phosphate** and **niacin (as NAD(P)H)**, are involved in glutamate synthesis.
Question 52: Which of the following is not a metabolic product of the urea cycle?
- A. Citrulline
- B. Arginine
- C. Alanine (Correct Answer)
- D. Ornithine
Explanation: ***Alanine*** - **Alanine** is an amino acid primarily involved in the **glucose-alanine cycle** for glucose production and ammonia transport, not as a direct metabolic product within the urea cycle. - While it plays a role in nitrogen metabolism, it is not synthesized or directly consumed as an intermediate in the reactions that convert ammonia to urea. *Citrulline* - **Citrulline** is a key intermediate formed during the second step of the urea cycle when **ornithine carbamoyltransferase** combines carbamoyl phosphate with ornithine. - It is then transported out of the mitochondrion into the cytosol to continue the cycle. *Ornithine* - **Ornithine** is an amino acid that acts as a **catalytic intermediate** in the urea cycle, being regenerated at the end of the cycle to combine with carbamoyl phosphate. - It does not directly contribute a nitrogen atom to urea but is essential for the cycle's continuation. *Arginine* - **Arginine** is an amino acid that is a direct precursor to urea in the penultimate step of the urea cycle, where **arginase** cleaves it into urea and ornithine. - It provides one of the nitrogen atoms and the carbon atom for the formation of urea.
Question 53: Which amino acid is not involved in transamination?
- A. Alanine
- B. Aspartate
- C. Lysine (Correct Answer)
- D. Histidine
Explanation: ***Lysine*** - **Lysine** cannot undergo transamination because it lacks the structural requirements for typical transaminase enzymes. - While lysine has both an **α-amino group** and an **ε-amino group**, its metabolic pathway involves **oxidative deamination** rather than transamination. - Along with **threonine**, lysine is one of only two amino acids that do not participate in transamination reactions. *Alanine* - **Alanine** is a major substrate for transamination, readily converting to pyruvate via **alanine transaminase (ALT)**. - This reaction involves the transfer of its **α-amino group** to an α-keto acid, typically α-ketoglutarate, forming glutamate. *Aspartate* - **Aspartate** is actively involved in transamination, converting to oxaloacetate via **aspartate transaminase (AST)**. - Its **α-amino group** is easily transferred to α-ketoglutarate, forming glutamate. *Histidine* - **Histidine** can undergo transamination, though less commonly cited as a primary substrate compared to aspartate and alanine. - It can transfer its **α-amino group** to an α-keto acid, leading to the formation of imidazolepyruvate.
Question 54: Boiled cabbage or rancid butter smelling urine is seen in
- A. Tyrosinemia
- B. Phenylketonuria
- C. Isovaleric Acidaemia (Correct Answer)
- D. Multiple carboxylase deficiency
Explanation: ***Isovaleric Acidaemia*** - **Boiled cabbage or rancid butter odor** in urine is a classic feature of isovaleric acidemia, caused by the accumulation of isovaleric acid. - This **inborn error of metabolism** affects **leucine metabolism** due to deficiency of isovaleryl-CoA dehydrogenase. *Tyrosinemia* - Does NOT present with boiled cabbage or rancid butter odor. The characteristic features are **liver dysfunction** and **renal tubular defects**. - Tyrosinemia Type I is caused by deficiency of **fumarylacetoacetate hydrolase**, leading to accumulation of tyrosine metabolites. *Phenylketonuria* - Characterized by a **mousy or musty odor** in urine, resulting from the accumulation of phenylacetic acid. - The defect is in the enzyme **phenylalanine hydroxylase**, not associated with boiled cabbage odor. *Multiple carboxylase deficiency* - Typically presents with a **"cat urine" smell** due to the accumulation of various organic acids. - The deficiency impairs the function of several **biotin-dependent carboxylases**, not specifically linked to the boiled cabbage odor.
Question 55: Apo B48 is synthesized in -
- A. Liver
- B. Kidney
- C. Intestine (Correct Answer)
- D. RBCs
Explanation: ***Intestine*** - **Apo B48** is a truncated form of apolipoprotein B-100, uniquely synthesized in the **intestine** through RNA editing. - It is a crucial structural component of **chylomicrons**, which are lipoprotein particles responsible for transporting exogenous dietary lipids from the intestine to other tissues. *Liver* - The liver primarily synthesizes **Apo B100**, which is a full-length apolipoprotein B and a major component of VLDL, IDL, and LDL. - It does not produce Apo B48. *Kidney* - The kidneys are involved in filtering waste products and regulating fluid balance, but they do not play a role in the synthesis of apolipoproteins like Apo B48. - Kidney cells are not equipped with the specific machinery for Apo B mRNA editing. *RBCs* - Red blood cells (RBCs) are primarily responsible for oxygen transport and lack a nucleus and most organelles, including those required for protein synthesis. - Therefore, RBCs cannot synthesize proteins such as Apo B48.
Question 56: What is the end product of purine metabolism in most mammals?
- A. Glycogen
- B. Pyrimidine
- C. Histidine
- D. Allantoin (Correct Answer)
Explanation: ***Allantoin*** - **Allantoin** is the primary end product of **purine metabolism** in **most mammals** (except humans and higher primates), formed by the oxidation of uric acid by the enzyme **uricase**. - This conversion makes purine waste products more **water-soluble** and easier to excrete via the kidneys. - **Important clinical note:** Humans lack functional uricase, so **uric acid** is the end product in humans; this distinction is why hyperuricemia and gout occur in humans but not in most other mammals. *Glycogen* - **Glycogen** is a complex carbohydrate and serves as a primary **energy storage molecule** in animals, derived from glucose metabolism, not purine catabolism. - Its metabolism is regulated by hormones like **insulin** and **glucagon**, involved in maintaining blood glucose levels. *Pyrimidine* - **Pyrimidine** is a type of nitrogenous base, structurally distinct from purines, and is a component of DNA and RNA, not an end product of purine catabolism. - **Pyrimidine metabolism** involves the synthesis and breakdown of bases like cytosine, thymine, and uracil, which follows a separate biochemical pathway. *Histidine* - **Histidine** is an **essential amino acid**, a building block of proteins, and is involved in various metabolic processes, including histamine synthesis. - It plays no role as an end product of purine degradation; rather, its own metabolism leads to products like **urocanic acid**.
Question 57: Which of the following statements is true regarding the sigma factor?
- A. It is a subunit of DNA polymerase.
- B. It is a subunit of RNA polymerase. (Correct Answer)
- C. It initiates DNA replication.
- D. It is a subunit of the 50s ribosome.
Explanation: ***It is a subunit of RNA polymerase.*** - The **sigma factor** is a crucial component of **bacterial RNA polymerase**, guiding it to specific promoter regions on the DNA. - It plays a vital role in **initiation of transcription** by recognizing and binding to the **-10 and -35 boxes** of the promoter. *It is a subunit of DNA polymerase.* - **DNA polymerase** is primarily involved in **DNA replication and repair**, not transcription. - Its subunits, such as the **beta clamp** or **alpha subunit**, are distinct from the sigma factor. *It initiates DNA replication.* - **DNA replication** is initiated by **DNA helicases** unwinding the double helix and **primase** synthesizing RNA primers. - The sigma factor's role is in **transcription**, the synthesis of RNA from a DNA template. *It is a subunit of the 50s ribosome.* - The **50S ribosomal subunit** is a component of the **ribosome**, responsible for **peptide bond formation** during translation. - Its subunits are ribosomal proteins and ribosomal RNA molecules, not the sigma factor.
Question 58: What is a key similarity between the processes of replication and transcription?
- A. Use RNA primers for initiation.
- B. Use ribonucleotides as precursors.
- C. Are semi-conservative events.
- D. Involve phosphodiester bond formation with elongation occurring in the 5' - 3' direction. (Correct Answer)
Explanation: ***Involve phosphodiester bond formation with elongation occurring in the 5' - 3' direction.*** - Both DNA replication and RNA transcription synthesize nucleic acid polymers by forming **phosphodiester bonds** between incoming nucleotides. - The new strand in both processes is always elongated in the **5' to 3' direction**, as new nucleotides are added to the 3' hydroxyl group of the growing strand. *Use RNA primers for initiation.* - **DNA replication** requires **RNA primers** to initiate synthesis of new DNA strands, as DNA polymerase cannot start a new strand *de novo*. - **Transcription (RNA synthesis)** does not require a primer; **RNA polymerase** can initiate transcription *de novo* at a promoter sequence. *Use ribonucleotides as precursors.* - **Transcription** uses **ribonucleotides** (ATP, UTP, CTP, GTP) as precursors to synthesize RNA. - **Replication** primarily uses **deoxyribonucleotides** (dATP, dTTP, dCTP, dGTP) to synthesize DNA, although it temporarily uses ribonucleotides for RNA primers. *Are semi-conservative events.* - **DNA replication** is a **semi-conservative process**, meaning each new DNA molecule consists of one original strand and one newly synthesized strand. - **Transcription** is **not semi-conservative**; it involves synthesizing an RNA molecule from a DNA template, leaving the original DNA template unchanged.
Question 59: What are Okazaki fragments?
- A. Long pieces of DNA on the lagging strand.
- B. Short pieces of DNA on the lagging strand. (Correct Answer)
- C. Short pieces of DNA on the leading strand.
- D. Long pieces of DNA on the leading strand.
Explanation: ***Short pieces of DNA on the lagging strand.*** - **Okazaki fragments** are the short, newly synthesized DNA fragments that are formed on the **lagging strand** during DNA replication. - The lagging strand is synthesized discontinuously because DNA polymerase can only add nucleotides in the **5' to 3' direction**, requiring it to move away from the replication fork as the DNA unwinds. *Long pieces of DNA on the lagging strand.* - The lagging strand is synthesized discontinuously in **short fragments**, not long continuous pieces. - The enzyme **DNA ligase** eventually joins these short fragments together to form a continuous strand. *Short pieces of DNA on the leading strand.* - The **leading strand** is synthesized continuously in one long stretch, moving towards the replication fork. - It does not require the synthesis of short fragments like the lagging strand. *Long pieces of DNA on the leading strand.* - While the leading strand is synthesized in a continuous, long piece, this statement does not accurately describe Okazaki fragments, which are specific to the lagging strand. - The leading strand's continuous synthesis is due to its **3' to 5' template orientation**, allowing DNA polymerase to proceed uninterrupted.
Question 60: What is the first purine nucleotide synthesized in de novo purine biosynthesis?
- A. AMP
- B. GMP
- C. IMP (Correct Answer)
- D. UMP
Explanation: ***IMP (Inosine Monophosphate)*** - **IMP** is the first complete purine nucleotide synthesized during the **de novo purine biosynthesis pathway**. - It serves as a branch point, from which **AMP** and **GMP** are subsequently synthesized through separate pathways. *AMP (Adenosine Monophosphate)* - **AMP** is a derivative of **IMP**, synthesized by the addition of an amino group from **aspartate** to IMP. - This step occurs after the formation of the complete purine ring structure in IMP. *GMP (Guanosine Monophosphate)* - **GMP** is also derived from **IMP**, through a pathway involving the oxidation of IMP to **XMP** (xanthosine monophosphate) and subsequent amination. - Its synthesis occurs downstream from IMP. *UMP (Uridine Monophosphate)* - **UMP** is a **pyrimidine nucleotide**, not a purine, and is synthesized via a completely different de novo pathway. - Pyrimidine biosynthesis involves forming the ring structure first, then attaching it to ribose-phosphate, unlike purine synthesis which builds the ring on a pre-existing ribose-phosphate.