NEET-PG 2012 - Radiology PYQs Practice Questions

Q: Half-life of iodine-131 is

8 days. ***8 days*** - The half-life of **iodine-131** is approximately 8.02 days, which makes it suitable for both diagnostic imaging and therapeutic applications in thyroid conditions. - This specific half-life allows sufficient time for the isotope to localize in the thyroid gland and deliver a therapeutic dose, while also ensuring it clears from the body relatively quickly to minimize long-term radiation exposure. *8 hours* - A half-life of 8 hours would be too short for many therapeutic applications of iodine-131, as it would decay too rapidly to deliver an effective dose to the thyroid. - Isotopes with such short half-lives are typically used for diagnostic imaging where rapid clearance and minimal patient exposure are paramount, such as **technetium-99m**. *8 weeks* - A half-life of 8 weeks would be excessively long for clinical use of iodine-131, leading to prolonged radiation exposure for the patient. - Such long half-lives increase the risk of adverse effects from cumulative radiation, making it unsuitable for routine diagnostic or therapeutic procedures. *8 months* - A half-life of 8 months is impractically long for any medical application requiring regular administration, as it would lead to very high and persistent radiation doses. - This duration would result in significant and unacceptable long-term radiation hazards, making its use unfeasible for imaging or therapy. [Practice more Radiology PYQs on OnCourse]

Q: Central stellate scar is typically associated with which of the following conditions?

Focal nodular hyperplasia (FNH). ***Focal nodular hyperplasia (FNH)*** - FNH is a benign liver lesion characterized by a central fibrous scar with radiating septa, giving it the characteristic appearance of a **central stellate scar** on imaging. - This scar contains **malformed blood vessels** and bile ductules, which are key diagnostic features. - On dynamic imaging, FNH typically shows **spoke-wheel arterial enhancement** pattern and the central scar shows **delayed enhancement** on MRI. *Hepatic adenoma* - Hepatic adenomas are typically composed of sheets of **hepatocytes** with absent portal triads and are usually **homogeneous** on imaging without a central scar. - They are associated with **oral contraceptive use** and have a risk of hemorrhage and malignant transformation. *Chronic liver disease* - Chronic liver disease, such as **cirrhosis**, is characterized by widespread **fibrosis** and **nodule formation** throughout the liver, but it does not typically present with a solitary lesion with a central stellate scar. - The scarring in cirrhosis is diffuse and leads to architectural distortion, rather than a focal central scar. *Hepatocellular carcinoma* - Hepatocellular carcinoma (HCC) typically presents as a **vascular mass** that may or may not be solitary, usually arising in the context of chronic liver disease or cirrhosis. - Although the **fibrolamellar variant of HCC** (seen in younger patients without cirrhosis) can show a central scar, this is less common and the scar typically shows **hypointensity on T2-weighted imaging**, unlike FNH where the scar is **hyperintense on T2**. - Typical HCC does not show a distinct central stellate scar as a characteristic feature. [Practice more Radiology PYQs on OnCourse]

Q: What is the primary mechanism of heat loss in a modern X-ray tube?

Radiation. ***Radiation*** - The **primary mechanism** of heat loss in a modern X-ray tube is **radiation** (infrared emission). - The anode surface reaches extremely high temperatures (>1000°C) during X-ray production, causing it to emit significant **infrared radiation**. - Modern X-ray tubes use **high-emissivity materials** (tungsten-rhenium alloys) on the anode to maximize radiative heat transfer. - Since the tube operates in a **vacuum**, radiation is the only effective mechanism for heat dissipation from the anode itself. *Evaporation* - **Evaporation** requires a liquid-to-gas phase change, which is not applicable in the solid-state environment of an X-ray tube anode. - The **vacuum environment** inside the tube prevents any evaporative cooling. - This mechanism is irrelevant for heat loss from the anode. *Conduction* - **Conduction** does transfer heat from the focal spot through the anode body to the rotor bearings. - However, this is heat transfer *within* the tube components, not the primary mechanism for heat loss *from the tube*. - Heat conducted through components must ultimately be dissipated by **radiation** (from anode) or **convection** (from housing via cooling oil). *Convection* - **Convection** requires fluid movement (liquid or gas), which cannot occur in the **vacuum** inside the X-ray tube envelope. - While cooling oil outside the tube uses convection to remove heat from the housing, this is secondary heat removal, not the primary mechanism of heat loss from the anode. - The anode loses heat primarily via **radiation** first, then that heat may be further managed by convection in the cooling system. [Practice more Radiology PYQs on OnCourse]

Q: What is the recommended thickness of lead apron to prevent radiation exposure?

0.5 mm. ***0.5 mm*** - A **0.5 mm lead equivalent apron** is the universally accepted standard for protecting against primary beam radiation in most medical imaging procedures, including fluoroscopy and interventional radiology. - This thickness provides adequate **radiation attenuation** to significantly reduce dose to the wearer while maintaining reasonable comfort and mobility. *1 mm* - While offering increased attenuation, a **1 mm lead equivalent apron** is considerably heavier and less practical for routine use, leading to greater physical strain without a proportional increase in necessary protection for most procedures. - The additional weight and bulk can hinder movement and reduce compliance, especially during long procedures. *3 mm* - A **3 mm lead equivalent apron** would be excessively heavy and restrictive for medical personnel, making it highly impractical for general use in radiology departments. - The degree of protection offered by such an apron far exceeds the requirements for standard diagnostic and interventional procedures, incurring unnecessary physical burden. *7 mm* - A **7 mm lead equivalent apron** is an extreme thickness that would be entirely unfeasible for an individual to wear due to its immense weight and stiffness. - This level of shielding is typically found in fixed architectural barriers for radiation protection, such as walls of an X-ray room, not in personal protective equipment. [Practice more Radiology PYQs on OnCourse]

Q: Which of the following techniques uses piezoelectric crystals?

Ultrasonography. ***Ultrasonography*** - **Piezoelectric crystals** are the core component of **ultrasound transducers**, which generate and detect ultrasonic waves. - These crystals convert electrical energy into mechanical vibrations (sound waves) and vice-versa, allowing for the creation of images. *NMR imaging* - **NMR imaging** (Nuclear Magnetic Resonance, now commonly known as **MRI**) uses strong magnetic fields and **radiofrequency pulses** to generate images. - It relies on the magnetic properties of atomic nuclei, particularly hydrogen, rather than piezoelectric effects. *X-ray diffraction* - **X-ray diffraction** is a technique used to study the atomic and molecular structure of materials, and it involves the interaction of **X-rays** with the electron clouds of atoms. - It does not involve piezoelectric crystals; instead, it uses an X-ray source and a detector to measure diffracted X-rays. *Xeroradiography* - **Xeroradiography** is an older imaging technique that used **xerographic plates** coated with a photoconductive material (like selenium) to capture X-ray images. - It relies on electrostatic charges and dry development rather than piezoelectric crystals to produce images. [Practice more Radiology PYQs on OnCourse]

Question 1

Half-life of iodine-131 is

Accepted Answer

8 days

Answer

8 hours

Answer

8 weeks

Answer

8 months

Question 2

Central stellate scar is typically associated with which of the following conditions?

Accepted Answer

Focal nodular hyperplasia (FNH)

Answer

Hepatic adenoma

Answer

Chronic liver disease

Answer

Hepatocellular carcinoma

Question 3

What is the primary mechanism of heat loss in a modern X-ray tube?

Accepted Answer

Radiation

Answer

Evaporation

Answer

Conduction

Answer

Convection

Question 4

What is the recommended thickness of lead apron to prevent radiation exposure?

Accepted Answer

0.5 mm

Answer

1 mm

Answer

3 mm

Answer

7 mm

Question 5

Which of the following techniques uses piezoelectric crystals?

Accepted Answer

Ultrasonography

Answer

NMR imaging

Answer

X-ray diffraction

Answer

Xeroradiography

Question 6

Rim sign in IVP is seen in

Accepted Answer

Hydronephrosis

Answer

Chronic Pyelonephritis

Answer

Renal Cell Carcinoma

Answer

Polycystic Kidney Disease

Question 7

Step ladder pattern of gas shadow is seen in

Accepted Answer

Intestinal obstruction

Answer

Gastric outlet obstruction

Answer

Duodenal obstruction

Answer

Sigmoid volvulus

Question 8

Investigation of choice for multiple sclerosis

Accepted Answer

MRI

Answer

CT

Answer

USG

Answer

PET

Question 9

What is the most effective imaging method for the diagnosis of adenomyosis?

Accepted Answer

MRI

Answer

CT scan

Answer

Hysterosalpingography

Answer

Ultrasound

Question 10

Which chamber enlargement shows a double right heart border with a wide subcarinal angle?

Accepted Answer

Left atrium

Answer

Left ventricle

Answer

Right atrium

Answer

Right ventricle

NEET-PG 2012 — Radiology