What is a key similarity between the processes of replication and transcription?
What are Okazaki fragments?
What is the first purine nucleotide synthesized in de novo purine biosynthesis?
C4, C5, and N7 in the purine ring are derived from which of the following?
What is the most important tool used in genetic engineering?
If the content of adenine (A) is 15%, what is the percentage of guanine (G) in the DNA?
The gaps between Okazaki fragments on the lagging strand during DNA replication are rejoined and sealed by:
By which enzyme is cDNA synthesized from RNA?
Which of the following is not classified as a chaperone protein?
Which of the following is NOT a function of glycosaminoglycans?
NEET-PG 2015 - Biochemistry NEET-PG Practice Questions and MCQs
Question 61: What is a key similarity between the processes of replication and transcription?
- A. Use RNA primers for initiation.
- B. Use ribonucleotides as precursors.
- C. Are semi-conservative events.
- D. Involve phosphodiester bond formation with elongation occurring in the 5' - 3' direction. (Correct Answer)
Explanation: ***Involve phosphodiester bond formation with elongation occurring in the 5' - 3' direction.*** - Both DNA replication and RNA transcription synthesize nucleic acid polymers by forming **phosphodiester bonds** between incoming nucleotides. - The new strand in both processes is always elongated in the **5' to 3' direction**, as new nucleotides are added to the 3' hydroxyl group of the growing strand. *Use RNA primers for initiation.* - **DNA replication** requires **RNA primers** to initiate synthesis of new DNA strands, as DNA polymerase cannot start a new strand *de novo*. - **Transcription (RNA synthesis)** does not require a primer; **RNA polymerase** can initiate transcription *de novo* at a promoter sequence. *Use ribonucleotides as precursors.* - **Transcription** uses **ribonucleotides** (ATP, UTP, CTP, GTP) as precursors to synthesize RNA. - **Replication** primarily uses **deoxyribonucleotides** (dATP, dTTP, dCTP, dGTP) to synthesize DNA, although it temporarily uses ribonucleotides for RNA primers. *Are semi-conservative events.* - **DNA replication** is a **semi-conservative process**, meaning each new DNA molecule consists of one original strand and one newly synthesized strand. - **Transcription** is **not semi-conservative**; it involves synthesizing an RNA molecule from a DNA template, leaving the original DNA template unchanged.
Question 62: What are Okazaki fragments?
- A. Long pieces of DNA on the lagging strand.
- B. Short pieces of DNA on the lagging strand. (Correct Answer)
- C. Short pieces of DNA on the leading strand.
- D. Long pieces of DNA on the leading strand.
Explanation: ***Short pieces of DNA on the lagging strand.*** - **Okazaki fragments** are the short, newly synthesized DNA fragments that are formed on the **lagging strand** during DNA replication. - The lagging strand is synthesized discontinuously because DNA polymerase can only add nucleotides in the **5' to 3' direction**, requiring it to move away from the replication fork as the DNA unwinds. *Long pieces of DNA on the lagging strand.* - The lagging strand is synthesized discontinuously in **short fragments**, not long continuous pieces. - The enzyme **DNA ligase** eventually joins these short fragments together to form a continuous strand. *Short pieces of DNA on the leading strand.* - The **leading strand** is synthesized continuously in one long stretch, moving towards the replication fork. - It does not require the synthesis of short fragments like the lagging strand. *Long pieces of DNA on the leading strand.* - While the leading strand is synthesized in a continuous, long piece, this statement does not accurately describe Okazaki fragments, which are specific to the lagging strand. - The leading strand's continuous synthesis is due to its **3' to 5' template orientation**, allowing DNA polymerase to proceed uninterrupted.
Question 63: What is the first purine nucleotide synthesized in de novo purine biosynthesis?
- A. AMP
- B. GMP
- C. IMP (Correct Answer)
- D. UMP
Explanation: ***IMP (Inosine Monophosphate)*** - **IMP** is the first complete purine nucleotide synthesized during the **de novo purine biosynthesis pathway**. - It serves as a branch point, from which **AMP** and **GMP** are subsequently synthesized through separate pathways. *AMP (Adenosine Monophosphate)* - **AMP** is a derivative of **IMP**, synthesized by the addition of an amino group from **aspartate** to IMP. - This step occurs after the formation of the complete purine ring structure in IMP. *GMP (Guanosine Monophosphate)* - **GMP** is also derived from **IMP**, through a pathway involving the oxidation of IMP to **XMP** (xanthosine monophosphate) and subsequent amination. - Its synthesis occurs downstream from IMP. *UMP (Uridine Monophosphate)* - **UMP** is a **pyrimidine nucleotide**, not a purine, and is synthesized via a completely different de novo pathway. - Pyrimidine biosynthesis involves forming the ring structure first, then attaching it to ribose-phosphate, unlike purine synthesis which builds the ring on a pre-existing ribose-phosphate.
Question 64: C4, C5, and N7 in the purine ring are derived from which of the following?
- A. CO₂
- B. Aspartate
- C. Glutamine
- D. Glycine (Correct Answer)
Explanation: ***Glycine*** - The entire **glycine molecule** contributes C4, C5, and N7 to the purine ring structure. - This amino acid provides a significant portion of the backbone to the imidazole ring within the purine. *Aspartate* - **Aspartate** contributes N1 to the purine ring. - It does not involve C4, C5, or N7, which are distinct atoms within the purine molecule. *CO₂* - **CO₂** contributes C6 to the purine ring through a carboxylation step. - It is not involved in providing the atoms at positions C4, C5, or N7. *Glutamine* - The nitrogen atoms N3 and N9 in the purine ring are derived from the **amide nitrogen of glutamine**. - Glutamine's contributions are different from the carbons and nitrogen provided by glycine.
Question 65: What is the most important tool used in genetic engineering?
- A. Topoisomerase
- B. DNA Ligase
- C. Restriction endonuclease (Correct Answer)
- D. Helicase
Explanation: ***Restriction endonuclease*** - **Restriction endonucleases** are crucial for genetic engineering as they specifically cut DNA at particular recognition sites, allowing the insertion or deletion of genes. - This precise cutting ability is fundamental for creating **recombinant DNA** molecules. *Helicase* - **Helicase** is primarily involved in unwinding the DNA double helix during processes like DNA replication and transcription. - While essential for cellular functions, it does not directly manipulate DNA for gene insertion or modification in the way restriction enzymes do. *Topoisomerase* - **Topoisomerase** enzymes are responsible for managing DNA supercoiling, preventing tangling during DNA replication and transcription by cutting and rejoining DNA strands. - It plays a role in DNA structure but is not directly used for targeted gene editing or insertion. *DNA Ligase* - **DNA ligase** is essential for joining DNA fragments, which is a critical step in genetic engineering after restriction endonucleases have cut the DNA. - However, while it acts as a "molecular glue" to seal nicks and re-form phosphodiester bonds, it cannot initiate the precise cutting required to isolate genes.
Question 66: If the content of adenine (A) is 15%, what is the percentage of guanine (G) in the DNA?
- A. 15%
- B. 85%
- C. 70%
- D. 35% (Correct Answer)
Explanation: ***35%*** - According to **Chargaff's rules**, in a DNA molecule, the amount of **adenine (A) is equal to the amount of thymine (T)**, and the amount of **guanine (G) is equal to the amount of cytosine (C)**. - If A = 15%, then T must also be 15%. This means A + T = 30%. Since the total percentage of all bases is 100%, G + C must be 100% - 30% = 70%. As G = C, then G = 70% / 2 = 35%. *15%* - This would only be correct if guanine paired with adenine, which it does not; guanine pairs with **cytosine**. - This answer incorrectly assumes that all four bases are present in equal proportions, or that G equals A, which violates **Chargaff's rules**. *85%* - This percentage would imply an incorrect base pairing or an imbalanced ratio of purines and pyrimidines, violating the fundamental structure of DNA. - An 85% guanine content would mean that G + C far exceeds 100% or that T is extremely low, which is biologically impossible. *70%* - This represents the combined percentage of **guanine and cytosine**, not guanine alone. - While it correctly acknowledges the remaining proportion of bases, it fails to divide this sum between the two equal components, **G and C**.
Question 67: The gaps between Okazaki fragments on the lagging strand during DNA replication are rejoined and sealed by:
- A. DNA Ligase (Correct Answer)
- B. DNA Helicase
- C. DNA Phosphorylase
- D. DNA Topoisomerase
Explanation: ***DNA Ligase*** - **DNA ligase** forms a **phosphodiester bond** between the **3'-OH group** of one Okazaki fragment and the **5'-phosphate group** of the adjacent fragment, effectively sealing the nicks. - After **DNA polymerase I** removes the **RNA primers** and fills in the gaps, DNA ligase completes the synthesis of the **lagging strand** during DNA replication. - This enzyme is essential for maintaining the **integrity of the DNA backbone**. *DNA Helicase* - **DNA helicase** functions to **unwind the DNA double helix**, separating the two strands to create a replication fork. - It does not participate in joining DNA fragments. *DNA Phosphorylase* - **DNA phosphorylase** is not a standard enzyme involved in the direct sealing of DNA fragments during replication. - This is not the enzyme responsible for ligating Okazaki fragments. *DNA Topoisomerase* - **DNA topoisomerase** relieves the **supercoiling tension** that builds up in the DNA double helix ahead of the replication fork due to unwinding. - It does not have a role in forming phosphodiester bonds between newly synthesized DNA fragments.
Question 68: By which enzyme is cDNA synthesized from RNA?
- A. Helicase
- B. DNA-dependent DNA polymerase
- C. Topoisomerase
- D. Reverse transcriptase (Correct Answer)
Explanation: ***Reverse transcriptase*** - **Reverse transcriptase** is a unique enzyme that synthesizes a **complementary DNA (cDNA)** strand from an **RNA template**. - This process, known as **reverse transcription**, is crucial in retroviruses and molecular biology techniques like RT-PCR. *Helicase* - **Helicase** enzymes are responsible for **unwinding nucleic acid double helices**, separating DNA strands during replication and transcription. - It does not synthesize DNA from an RNA template. *DNA-dependent DNA polymerase* - **DNA-dependent DNA polymerase** synthesizes new **DNA strands using an existing DNA template** during DNA replication. - It cannot use RNA as a template to synthesize DNA. *Topoisomerase* - **Topoisomerase** enzymes are involved in **managing DNA supercoiling** by creating transient breaks in the DNA backbone. - They do not synthesize DNA from any template.
Question 69: Which of the following is not classified as a chaperone protein?
- A. Calnexin
- B. Protein disulfide isomerase
- C. Calreticulin
- D. Calbindin (Correct Answer)
Explanation: ***Calbindin*** - **Calbindin** is a **calcium-binding protein** that helps regulate intracellular calcium levels, particularly in the brain and intestines. - It does not assist in **protein folding** or assembly like chaperone proteins. *Calnexin* - **Calnexin** is a **chaperone protein** located in the endoplasmic reticulum (ER). - It assists in the proper folding and quality control of newly synthesized **glycoproteins**. *Protein disulfide isomerase* - **Protein disulfide isomerase (PDI)** is an ER enzyme that **catalyzes the formation and rearrangement of disulfide bonds** in newly synthesized proteins, which is crucial for proper folding. - Due to its role in enabling correct protein folding, it is considered a **chaperone-like protein**. *Calreticulin* - **Calreticulin** is another **calcium-binding chaperone protein** found in the endoplasmic reticulum. - It works synergistically with calnexin to ensure the **proper folding of glycoproteins**.
Question 70: Which of the following is NOT a function of glycosaminoglycans?
- A. Lubrication of joints
- B. Wound healing process
- C. Anticoagulant activity
- D. Transport of lipids in the bloodstream (Correct Answer)
Explanation: ***Transport of lipids in the bloodstream*** - Glycosaminoglycans (GAGs) generally do not play a direct role in the **transport of lipids** in the bloodstream. Lipid transport is primarily mediated by **lipoproteins** (e.g., chylomicrons, VLDL, LDL, HDL). - While some GAGs might interact with lipoproteins in the extracellular matrix, their fundamental role is not lipid transport but rather structural and signaling functions. *Lubrication of joints* - This is a well-established function of GAGs, particularly **hyaluronic acid**, which contributes to the **viscoelastic properties of synovial fluid**, reducing friction in joints. - Hyaluronic acid helps maintain the **hydration** and **shock-absorbing capacity** of articular cartilage. *Wound healing process* - Glycosaminoglycans, especially **hyaluronic acid** and **heparin sulfate**, are crucial in **wound healing** processes, where they modulate inflammation, cell migration, and tissue remodeling. - They provide a **scaffold for cell proliferation** and differentiation in the wound bed. *Anticoagulant activity* - **Heparin**, a highly sulfated glycosaminoglycan, is a potent **anticoagulant** that works by activating **antithrombin III**, thereby inhibiting various coagulation factors like thrombin. - Other GAGs, like **heparan sulfate** found on cell surfaces, also exhibit mild anticoagulant properties.