Optics and Refraction Practice Questions

Q: What is the normal refractive power of the human eye?

58 Diopters. **Explanation:** The total refractive power of the human eye is approximately **+58 to +60 Diopters (D)**. This power is essential for focusing parallel rays of light onto the retina to form a clear image. The eye acts as a compound lens system where the two primary refractive components are: 1. **The Cornea:** Provides about **+43 D** (roughly 75% of the total power). It has the highest refractive power because of the significant difference in the refractive index between air (1.0) and the corneal epithelium (1.376). 2. **The Crystalline Lens:** Provides about **+15 to +19 D** in its resting state. **Analysis of Options:** * **Option A (20 D):** This is incorrect as it represents only the approximate power of the crystalline lens alone, not the entire eye. * **Option B (35 D):** This value does not correspond to any standard physiological measurement of the eye's refractive components. * **Option C (18 D):** This is the approximate power of the lens in an emmetropic eye. It is also the standard power of a posterior chamber Intraocular Lens (IOL) used during cataract surgery to replace the natural lens. * **Option D (58 D):** This is the **correct** total refractive power of the "Gullstrand’s Reduced Eye" model, a simplified schematic used in clinical optics. **Clinical Pearls for NEET-PG:** * **Reduced Eye Model:** A simplified model where the eye is treated as a single refracting surface with a focal length of **17 mm** and a total power of **+58.6 D**. * **Refractive Indices:** Air (1.0), Cornea (1.376), Aqueous/Vitreous (1.336), and Lens (1.386–1.406). * **Aphakia:** When the lens is removed, the eye loses ~18 D of power, becoming highly hypermetropic. * **Accommodation:** The lens can increase its power (up to +14 D in children) to focus on near objects, a process that declines with age (Presbyopia).

Q: What is the total refractory power of the crystalline lens at rest with accommodation?

16D. **Explanation:** The total refractive power of the human eye is approximately **+58 to +60 Diopters (D)**. This power is primarily derived from two structures: the cornea and the crystalline lens. 1. **The Cornea:** Contributes about **+43D to +44D** (roughly two-thirds of the total power). 2. **The Crystalline Lens:** In its **resting state** (unaccommodated), the lens provides approximately **+15D to +16D** of refractive power. The question asks for the power "at rest," which refers to the state where the ciliary muscles are relaxed and the zonules are taut, keeping the lens in its least convex form. While some textbooks cite 15D, **16D** is the standard accepted value in most clinical ophthalmology references and competitive exams for the lens's resting refractive contribution. **Analysis of Options:** * **A (14D):** This is slightly below the average physiological range for a healthy adult lens. * **C & D (18D & 20D):** These values represent the lens power during **active accommodation**. During accommodation, the ciliary muscle contracts, zonules relax, and the lens becomes more spherical, increasing its power by approximately +10D to +14D in children (decreasing with age). **High-Yield Clinical Pearls for NEET-PG:** * **Refractive Index:** The crystalline lens has a gradient refractive index, but the average is **1.39**, while the cornea is **1.37**. * **Radius of Curvature:** At rest, the anterior surface radius is **10 mm**, and the posterior surface is **6 mm**. * **Aphakia:** If the lens is removed (aphakia), the eye loses its +16D power, requiring a high-plus spectacle correction (approx. +10D at the spectacle plane). * **Accommodation:** The maximum accommodative power is highest at birth and reaches zero around age 60 (Presbyopia).

Q: Which structure of the eye has the highest refractive index?

Lens. **Explanation:** The refractive index of a medium is a measure of how much it slows down and bends light. In the human eye, the **Lens** has the highest refractive index, ranging from approximately **1.386 at the cortex to 1.406 at the inner nucleus**. This gradient is due to the high concentration of crystallin proteins, particularly in the nucleus. **Analysis of Options:** * **Lens (Correct):** While the cornea provides the most refractive *power* (approx. 43D), the lens material itself is denser, giving it the highest refractive *index* (average 1.39–1.40). * **Cornea:** It has a refractive index of **1.376**. Although lower than the lens, it provides more refractive power because of the vast difference in refractive index between the air (1.0) and the corneal surface. * **Aqueous Humor:** It is a watery fluid with a refractive index of **1.336**, which is very similar to water. * **Vitreous Humor:** Like the aqueous, it consists mostly of water and has a refractive index of **1.336**. **High-Yield Clinical Pearls for NEET-PG:** 1. **Total Refractive Power of the Eye:** Approximately **+58 to +60 Diopters**. 2. **Corneal Power:** +43 to +44 D (Main contributor to static refraction). 3. **Lens Power:** +15 to +19 D (Responsible for dynamic refraction/accommodation). 4. **Reduced Eye:** A simplified model where the eye is treated as a single refracting surface with a total power of +60D and a nodal point 17mm in front of the retina. 5. **Index Myopia:** An increase in the refractive index of the lens (e.g., in nuclear cataracts) causes a myopic shift, often leading to "second sight" in elderly patients.

Q: Which of the following is a prescription for simple myopic astigmatism?

-0.50 x 180°. ### Explanation To identify the correct prescription for **Simple Myopic Astigmatism (SMA)**, one must understand the refractive state of the eye in this condition. In SMA, one principal meridian is emmetropic (focuses on the retina), while the other is myopic (focuses in front of the retina). **1. Why Option A is Correct:** * **The Cylinder:** Astigmatism is corrected using a **cylindrical lens**, which has power in only one meridian. * **The Sign:** A **minus (-)** sign indicates myopia. * **The Prescription:** `-0.50 x 180°` means there is a myopic correction of 0.50 Diopters in the vertical meridian, while the horizontal meridian has zero power. This perfectly describes simple myopic astigmatism. **2. Analysis of Incorrect Options:** * **Option B (+0.50 x 180°):** This is a plus cylinder. It represents **Simple Hypermetropic Astigmatism**, where one meridian is emmetropic and the other is hypermetropic (focuses behind the retina). * **Option C (-3.00 D):** This is a spherical lens. It represents **Simple Myopia** (no astigmatism), where all meridians are equally myopic. * **Option D (+2.00 D):** This is a spherical lens representing **Simple Hypermetropia**. **3. High-Yield Clinical Pearls for NEET-PG:** * **Astigmatism Classification:** * **Simple:** One focal line on the retina; the other in front (myopic) or behind (hypermetropic). * **Compound:** Both focal lines are either in front of or behind the retina (e.g., -2.00 DS / -1.00 DC). * **Mixed:** One focal line is in front and the other is behind the retina (e.g., +2.00 DS / -3.00 DC). * **Rule of Thumb:** If the prescription contains *only* a minus cylinder (and no sphere), it is Simple Myopic Astigmatism. * **Sturm’s Conoid:** The geometric configuration of light rays in an astigmatic eye. The distance between the two focal lines is called the **Focal Interval of Sturm**.

Q: What is the total number of refractive surfaces in the human eye?

Four. ### Explanation The human eye acts as a complex optical system where light is refracted at every interface between two media with different refractive indices. **Why "Four" is the Correct Answer:** According to the **Gullstrand’s Schematic Eye**, there are four primary refractive surfaces that light must pass through to reach the retina: 1. **Anterior surface of the cornea:** The interface between air and the corneal epithelium (the most powerful refractive surface). 2. **Posterior surface of the cornea:** The interface between the corneal endothelium and the aqueous humor. 3. **Anterior surface of the lens:** The interface between the aqueous humor and the lens capsule. 4. **Posterior surface of the lens:** The interface between the lens and the vitreous humor. **Analysis of Incorrect Options:** * **Two:** This refers to the **Reduced Eye** model (Listing’s), which simplifies the eye into a single refracting surface (the cornea) and a single lens. While useful for calculations, it does not represent the anatomical reality. * **Three/Five:** These do not correspond to any standard physiological or schematic model of the eye’s optical system. **Clinical Pearls for NEET-PG:** * **Total Refractive Power:** The total power of the schematic eye is approximately **+58 to +60 Diopters (D)**. * **Corneal Power:** The cornea contributes about **+43 D** (roughly 70% of total power). * **Lens Power:** The crystalline lens contributes about **+15 to +20 D** in a relaxed state. * **Refractive Indices:** Air (1.00), Cornea (1.376), Aqueous/Vitreous (1.336), and Lens (1.41). * **Nodal Point:** In the schematic eye, the nodal point is located approximately **17 mm** in front of the retina.

Q: What is the refractive index of the cornea?

1.37. **Explanation:** The refractive index of a medium determines how much light bends as it enters that medium. The **cornea** is the primary refractive element of the eye, accounting for approximately **+43 Diopters** (roughly 70%) of the eye's total refractive power. 1. **Why 1.37 is Correct:** The refractive index of the corneal tissue (specifically the stroma) is **1.376**. This value is crucial because the greatest change in refractive index occurs at the air-tear film interface (1.0 to 1.33), which is why the anterior surface of the cornea provides the bulk of the eye's focusing power. 2. **Analysis of Incorrect Options:** * **1.33 (Option B):** This is the refractive index of **water, the aqueous humor, and the vitreous humor**. While the cornea is 78% water, its collagenous structure gives it a slightly higher index. * **1.42 (Option C):** This is the refractive index of the **crystalline lens core (nucleus)**. The lens has a "gradient" refractive index, ranging from approximately 1.38 at the cortex to 1.42 at the center. * **1.45 (Option D):** This value is higher than any natural refractive media in the human eye. **High-Yield Clinical Pearls for NEET-PG:** * **Total Refractive Power of Eye:** +58 to +60 D. * **Corneal Power:** +43 D (Anterior surface: +48 D; Posterior surface: -5 D). * **Reduced Eye (Listing’s Eye):** A simplified model where the eye is treated as a single refracting surface with a refractive index of **1.33** and a total power of **+60 D**. * **Radius of Curvature:** The anterior surface of the cornea is approximately **7.8 mm**.

Q: Which of the following is true about degenerative myopia?

Myopic degeneration can lead to retinal detachment. **Explanation:** Degenerative (Pathological) myopia is characterized by progressive axial elongation of the eyeball, typically exceeding **26.5 mm** in length or a refractive error of **>-6 Diopters**. **Why Option B is Correct:** The hallmark of degenerative myopia is the stretching of the posterior segment. As the eyeball elongates, the retina and choroid undergo thinning and atrophy. This stretching leads to peripheral retinal degenerations, most notably **Lattice degeneration**. These weakened areas are prone to developing retinal holes or tears, which allow fluid to enter the subretinal space, leading to **Rhegmatogenous Retinal Detachment (RRD)**. **Analysis of Incorrect Options:** * **Option A:** Degenerative myopia is actually **more common in females** than in males. * **Option C:** It is defined by a refractive error **greater than -6 Diopters** (e.g., -8D, -10D). High myopia is the prerequisite for degenerative changes. * **Option D:** Instead of swelling, the optic disc typically shows **Myopic Crescent** (temporal or annular) and may appear tilted. The stretching often leads to posterior staphyloma, not edema. **High-Yield Clinical Pearls for NEET-PG:** * **Posterior Staphyloma:** The pathognomonic sign of degenerative myopia (bulging of the weakened sclera). * **Fuchs’ Spots:** Pigmented circular lesions at the macula caused by subretinal neovascularization and hemorrhage. * **Lacquer Cracks:** Linear breaks in the Bruch’s membrane. * **Vitreous:** Early liquefaction (syneresis) and Posterior Vitreous Detachment (PVD) are common.

Q: On performing refraction using a plane mirror on a patient with a refractive error of –3 D sphere with –2 D cylinder at 90 degrees from a distance of 1 metre under no cycloplegia, in which direction would the reflex be seen to move?

Against the movement in both axes. ### Explanation **1. Understanding the Concept (The "Neutral Point")** In retinoscopy (using a plane mirror), the direction of the reflex movement depends on the patient's refractive error relative to the **working distance**. * The "Neutral Point" at 1 meter corresponds to **–1.0 D**. * If the myopia is **less than –1.0 D** (or hypermetropia), we see **"With"** movement. * If the myopia is **more than –1.0 D** (more negative), we see **"Against"** movement. **2. Analyzing the Question** The patient has a refractive error of **–3.0 DS / –2.0 DC @ 90°**. Let’s calculate the power in both principal meridians: * **Vertical Meridian (90°):** The power acting here is the sphere alone = **–3.0 D**. * **Horizontal Meridian (180°):** The power acting here is the sum of sphere + cylinder = (–3.0) + (–2.0) = **–5.0 D**. Since both meridians (–3.0 D and –5.0 D) are **more myopic than –1.0 D** (the neutral point at 1m), the reflex will move **Against** the movement of the mirror in both axes. **3. Why Other Options are Wrong** * **Option B:** "With" movement in both axes would occur if both meridians were less than –1.0 D (e.g., –0.5 D or +2.0 D). * **Options A & D:** These describe mixed movement. This would only occur if one meridian was more than –1.0 D and the other was less than –1.0 D (e.g., –0.5 D and –2.0 D). **Clinical Pearls for NEET-PG:** * **Plane Mirror vs. Concave Mirror:** A plane mirror gives "With" movement in hypermetropia; a concave mirror (at 1m) gives "Against" movement in hypermetropia. * **Working Distance Formula:** Neutrality (D) = 1 / Distance (meters). At 66 cm, the neutral point is –1.5 D. * **Static Retinoscopy:** Performed without cycloplegia (as in this question), the patient must fixate at infinity to relax accommodation.

Question 1

While performing a duochrome test, if the patient reports that he sees red letters more clearly than green, it indicates that he is slightly:

Accepted Answer

Myopic

Answer

Hypermetropic

Answer

Presbyopic

Answer

Emmetropic

Question 2

What is the normal refractive power of the human eye?

Accepted Answer

58 Diopters

Answer

20 Diopters

Answer

35 Diopters

Answer

18 Diopters

Question 3

What is the total refractory power of the crystalline lens at rest with accommodation?

Accepted Answer

16D

Answer

14D

Answer

18D

Answer

20D

Question 4

Which structure of the eye has the highest refractive index?

Accepted Answer

Lens

Answer

Cornea

Answer

Aqueous humor

Answer

Vitreous humor

Question 5

Which of the following is a prescription for simple myopic astigmatism?

Accepted Answer

-0.50 x 180°

Answer

+0.50 x 180°

Answer

-3.00 D

Answer

+2.00 D

Question 6

What is the total number of refractive surfaces in the human eye?

Accepted Answer

Four

Answer

Two

Answer

Five

Answer

Three

Question 7

What is the refractive index of the cornea?

Accepted Answer

1.37

Answer

1.33

Answer

1.42

Answer

1.45

Question 8

What will be the prescription of spectacles in a patient having simple hypermetropia with regular astigmatism?

Accepted Answer

+3.00 D at 180 degrees

Answer

-2.00 D at 180 degrees

Answer

-0.50 D at 90 degrees

Answer

+1.00 D at 90 degrees

Question 9

Which of the following is true about degenerative myopia?

Accepted Answer

Myopic degeneration can lead to retinal detachment

Answer

More common in males as compared to females

Answer

It is seen in <-6 Diopters myopia

Answer

Optic disc swelling is seen

Question 10

On performing refraction using a plane mirror on a patient with a refractive error of –3 D sphere with –2 D cylinder at 90 degrees from a distance of 1 metre under no cycloplegia, in which direction would the reflex be seen to move?

Accepted Answer

Against the movement in both axes

Answer

With the movement in the horizontal axis and against the movement in the vertical axis

Answer

With the movement in both axes

Answer

With the movement in the vertical axis and against the movement in the horizontal axis

Optics and Refraction — MCQs

Optics and Refraction — MCQs

On this page

Practice by Chapter

Want unlimited practice?