V/Q ratio and gas exchange US Medical PG Practice Questions and MCQs
Practice US Medical PG questions for V/Q ratio and gas exchange. These multiple choice questions (MCQs) cover important concepts and help you prepare for your exams.
V/Q ratio and gas exchange US Medical PG Question 1: A 21-year-old man presents to his physician because he has been feeling increasingly tired and short of breath at work. He has previously had these symptoms but cannot recall the diagnosis he was given. Chart review reveals the following results:
Oxygen tension in inspired air = 150 mmHg
Alveolar carbon dioxide tension = 50 mmHg
Arterial oxygen tension = 71 mmHg
Respiratory exchange ratio = 0.80
Diffusion studies reveal normal diffusion distance. The patient is administered 100% oxygen but the patient's blood oxygen concentration does not improve. Which of the following conditions would best explain this patient's findings?
- A. Septal defect since birth (Correct Answer)
- B. Use of opioid medications
- C. Pulmonary fibrosis
- D. Pulmonary embolism
- E. Vacation at the top of a mountain
V/Q ratio and gas exchange Explanation: ***Septal defect since birth***
- A congenital heart disease like a **septal defect** causes a right-to-left **shunt**, meaning deoxygenated blood bypasses the lungs and mixes with oxygenated blood.
- This type of shunt leads to **hypoxemia that is refractory to 100% oxygen** because the shunted blood will never pick up oxygen from the lungs.
*Use of opioid medications*
- Opioid use causes **respiratory depression**, leading to **hypoventilation** and increased arterial CO2 with decreased arterial O2.
- However, the hypoxemia from hypoventilation would typically improve significantly with **100% oxygen administration**, unlike in this case.
*Pulmonary fibrosis*
- **Pulmonary fibrosis** causes thickening of the alveolar-capillary membrane, leading to impaired gas exchange and **diffusion limitation**.
- While it causes hypoxemia, the diffusion studies are stated to be **normal**, and hypoxemia due to diffusion limitation often improves with supplemental oxygen.
*Pulmonary embolism*
- A **pulmonary embolism** leads to V/Q mismatch by blocking blood flow to a portion of the lung, causing ventilation with no perfusion.
- Hypoxemia from V/Q mismatch generally **responds well to supplemental oxygen**, as the non-affected lung areas can compensate, unlike the scenario described.
*Vacation at the top of a mountain*
- Being at a high altitude causes **hypobaric hypoxia**, meaning there is a reduced partial pressure of oxygen in the inspired air.
- This type of hypoxemia typically **improves with supplemental oxygen** as it increases the inspired oxygen tension, which is contrary to the patient's findings.
V/Q ratio and gas exchange US Medical PG Question 2: A 35-year-old woman volunteers for a study on respiratory physiology. Pressure probes A and B are placed as follows:
Probe A: between the parietal and visceral pleura
Probe B: within the cavity of an alveolus
The probes provide a pressure reading relative to atmospheric pressure. To obtain a baseline reading, she is asked to sit comfortably and breathe normally. Which of the following sets of values will most likely be seen at the end of inspiration?
- A. Probe A: -6 mm Hg; Probe B: 0 mm Hg (Correct Answer)
- B. Probe A: 0 mm Hg; Probe B: -1 mm Hg
- C. Probe A: -4 mm Hg; Probe B: 0 mm Hg
- D. Probe A: -4 mm Hg; Probe B: -1 mm Hg
- E. Probe A: -6 mm Hg; Probe B: -1 mm Hg
V/Q ratio and gas exchange Explanation: ***Probe A: -6 mm Hg; Probe B: 0 mm Hg***
- At the **end of inspiration**, the **intrapleural pressure (Probe A)** is at its most negative, typically around -6 to -8 cm H2O (equivalent to -4 to -6 mmHg), reflecting the maximum expansion of the thoracic cavity.
- At the **end of inspiration**, just before exhalation begins, there is **no airflow**, so the **intrapulmonary pressure (Probe B)** equalizes with atmospheric pressure, resulting in a 0 mm Hg reading.
*Probe A: 0 mm Hg; Probe B: -1 mm Hg*
- An **intrapleural pressure of 0 mm Hg** would indicate a **pneumothorax** since it should always be negative to prevent lung collapse.
- An **intrapulmonary pressure of -1 mm Hg** would indicate that **inspiration is still ongoing**, as air would be flowing into the lungs.
*Probe A: -4 mm Hg; Probe B: 0 mm Hg*
- While an **intrapulmonary pressure of 0 mm Hg** is correct at the end of inspiration, an **intrapleural pressure of -4 mm Hg** is typical for the **end of expiration (Functional Residual Capacity)** during quiet breathing, not the end of inspiration.
- The **intrapleural pressure becomes more negative** during inspiration due to increased thoracic volume, so -4 mm Hg would be insufficient.
*Probe A: -4 mm Hg; Probe B: -1 mm Hg*
- An **intrapleural pressure of -4 mm Hg** is the normal pressure at the **end of expiration**, not the end of inspiration, where it becomes more negative.
- An **intrapulmonary pressure of -1 mm Hg** indicates that **inspiration is still in progress**, not at its end, as air would still be flowing into the lungs.
*Probe A: -6 mm Hg; Probe B: -1 mm Hg*
- While an **intrapleural pressure of -6 mm Hg** is consistent with the end of inspiration, an **intrapulmonary pressure of -1 mm Hg** means that **airflow is still occurring into the lungs**.
- At the **very end of inspiration**, just before the start of exhalation, airflow momentarily ceases, and intrapulmonary pressure becomes zero relative to the atmosphere.
V/Q ratio and gas exchange US Medical PG Question 3: In which of the following pathological states would the oxygen content of the trachea resemble the oxygen content in the affected alveoli?
- A. Emphysema
- B. Exercise
- C. Pulmonary embolism (Correct Answer)
- D. Pulmonary fibrosis
- E. Foreign body obstruction distal to the trachea
V/Q ratio and gas exchange Explanation: ***Pulmonary embolism***
- A pulmonary embolism blocks **blood flow** to a portion of the lung, creating **dead space ventilation** (high V/Q ratio).
- In the affected alveoli, **no blood perfusion** means no oxygen extraction occurs, so the alveolar oxygen content remains **high and similar to tracheal/inspired air**.
- This is the classic physiological state where ventilation continues but perfusion is absent, preventing gas exchange.
*Foreign body obstruction distal to the trachea*
- A complete obstruction **prevents fresh air** from reaching the affected alveoli.
- The trapped gas undergoes **resorption atelectasis**: oxygen is absorbed into capillary blood, CO2 diffuses in, and alveolar gas equilibrates with **venous blood** composition.
- Alveolar oxygen content becomes **very low**, not similar to tracheal air.
*Emphysema*
- Emphysema involves destruction of **alveolar walls** and enlargement of airspaces with impaired gas exchange.
- While V/Q mismatch occurs, oxygen is still extracted by perfusing blood.
- Alveolar oxygen content is **lower than tracheal air** due to ongoing (though inefficient) gas exchange.
*Exercise*
- During exercise, **oxygen consumption increases** dramatically with enhanced cardiac output and oxygen extraction.
- Alveolar oxygen content is **significantly lower** than tracheal air due to increased oxygen uptake by blood.
*Pulmonary fibrosis*
- Pulmonary fibrosis causes **thickening of the alveolar-capillary membrane**, impairing oxygen diffusion.
- Despite diffusion limitation, blood still perfuses the alveoli and extracts oxygen.
- Alveolar oxygen content is **lower than tracheal air**, though the A-a gradient is increased.
V/Q ratio and gas exchange US Medical PG Question 4: A 72-year-old obese man presents as a new patient to his primary care physician because he has been feeling tired and short of breath after recently moving to Denver. He is a former 50 pack-year smoker and has previously had deep venous thrombosis. Furthermore, he previously had a lobe of the lung removed due to lung cancer. Finally, he has a family history of a progressive restrictive lung disease. Laboratory values are obtained as follows:
Oxygen tension in inspired air = 130 mmHg
Alveolar carbon dioxide tension = 48 mmHg
Arterial oxygen tension = 58 mmHg
Respiratory exchange ratio = 0.80
Respiratory rate = 20/min
Tidal volume = 500 mL
Which of the following mechanisms is consistent with these values?
- A. Shunt physiology
- B. High altitude
- C. V/Q mismatch
- D. Pulmonary fibrosis
- E. Hypoventilation (Correct Answer)
V/Q ratio and gas exchange Explanation: ***Hypoventilation***
- The arterial oxygen tension (PaO2) of 58 mmHg is consistent with hypoxemia, and the alveolar carbon dioxide tension (PACO2) of 48 mmHg (normal 35-45 mmHg) indicates **hypercapnia**, a hallmark of hypoventilation.
- The **alveolar-arterial (A-a) gradient** can be calculated using the alveolar gas equation: PAO2 = PiO2 - PACO2/R. Here, PAO2 = 130 mmHg - 48 mmHg/0.8 = 130 - 60 = 70 mmHg. The A-a gradient is PAO2 - PaO2 = 70 - 58 = 12 mmHg, which is within the normal range (5-15 mmHg), indicating that the hypoxemia is primarily due to **decreased alveolar ventilation**.
*Shunt physiology*
- A shunt would cause a significant reduction in PaO2 and a **widened A-a gradient** (typically >15 mmHg) due to deoxygenated blood bypassing ventilated areas.
- While shunts do not typically cause hypercapnia unless very severe, the normal A-a gradient here rules out a significant shunt as the primary mechanism for hypoxemia.
*High altitude*
- Moving to a high altitude (like Denver) causes a decrease in **inspired oxygen tension (PiO2)**, leading to hypoxemia.
- However, the provided inspired oxygen tension (130 mmHg) is above what would be expected for significant high-altitude hypoxemia at sea level equivalent, and the hypoxemia here is associated with hypercapnia, which is not a direct result of high altitude itself.
*V/Q mismatch*
- A V/Q mismatch leads to hypoxemia and a **widened A-a gradient**, as some areas of the lung are either underventilated or underperfused.
- While it can cause hypoxemia, a V/Q mismatch is typically associated with **normal or low PaCO2** due to compensatory hyperventilation, not hypercapnia, and the A-a gradient would be elevated.
*Pulmonary fibrosis*
- Pulmonary fibrosis is a restrictive lung disease that leads to impaired gas exchange, causing hypoxemia primarily due to **V/Q mismatch** and **diffusion limitation**.
- This would result in a **widened A-a gradient** and often a **low PaCO2** due to compensatory hyperventilation, rather than the elevated PaCO2 observed in this patient.
V/Q ratio and gas exchange US Medical PG Question 5: A 68-year-old man comes to the emergency room with difficulty in breathing. He was diagnosed with severe obstructive lung disease a few years back. He uses his medication but often has to come to the emergency room for intravenous therapy to help him breathe. He was a smoker for 40 years smoking two packs of cigarettes every day. Which of the following best represents the expected changes in his ventilation, perfusion and V/Q ratio?
- A. Normal ventilation, low or nonexistent perfusion and infinite V/Q ratio
- B. Medium ventilation and perfusion, V/Q that equals 0.8
- C. Higher ventilation and perfusion with lower V/Q ratio
- D. Low ventilation, normal perfusion and low V/Q ratio (Correct Answer)
- E. Lower ventilation and perfusion, but higher V/Q ratio
V/Q ratio and gas exchange Explanation: ***Low ventilation, normal perfusion and low V/Q ratio***
- In severe **obstructive lung disease** (like COPD), there is airflow limitation, leading to areas of **hypoventilation** in the lungs.
- While ventilation is compromised, blood flow (perfusion) to these areas can remain relatively normal, resulting in a **decreased V/Q ratio**.
*Normal ventilation, low or nonexistent perfusion and infinite V/Q ratio*
- This scenario describes a lung unit with **dead space ventilation**, where there is ventilation but no blood flow (e.g., in a pulmonary embolism).
- The patient's history of **obstructive lung disease** primarily indicates impaired airflow, not a lack of perfusion.
*Medium ventilation and perfusion, V/Q that equals 0.8*
- A **V/Q ratio of 0.8** represents the **ideal normal** ventilation-perfusion matching in a healthy lung.
- The patient has severe obstructive lung disease, which by definition means there is significant mismatch, not normal physiology.
*Higher ventilation and perfusion with lower V/Q ratio*
- While hyperventilation can occur in attempts to compensate, the primary issue in obstructive disease is **impaired ventilation**, not increased ventilation, leading to decreased gas exchange.
- A lower V/Q ratio is expected, but it is driven by **low ventilation**, not higher ventilation and perfusion.
*Lower ventilation and perfusion, but higher V/Q ratio*
- Although both ventilation and perfusion can be affected in severe disease, a **higher V/Q ratio** typically implies areas of increased dead space (more ventilation than perfusion).
- In obstructive disease, the predominant problem is **impaired air entry**, leading to underventilated units with relatively preserved perfusion, thus a **low V/Q ratio**.
V/Q ratio and gas exchange US Medical PG Question 6: During a clinical study examining the diffusion of gas between the alveolar compartment and the pulmonary capillary blood, men between the ages of 20 and 50 years are evaluated while they hold a sitting position. After inhaling a water-soluble gas that rapidly combines with hemoglobin, the concentration of the gas in the participant's exhaled air is measured and the diffusion capacity is calculated. Assuming that the concentration of the inhaled gas remains the same, which of the following is most likely to increase the flow of the gas across the alveolar membrane?
- A. Deep exhalation
- B. Entering a cold chamber
- C. Treadmill exercise (Correct Answer)
- D. Standing straight
- E. Assuming a hunched position
V/Q ratio and gas exchange Explanation: ***Correct: Treadmill exercise***
- **Treadmill exercise** increases cardiac output and pulmonary blood flow, which in turn recruits and distends more **pulmonary capillaries**. This increases the **surface area** available for gas exchange and reduces the diffusion distance, thereby enhancing the flow of gas across the alveolar membrane.
- Exercise also typically leads to deeper and more frequent breaths, increasing the **ventilation-perfusion matching** and overall efficiency of gas exchange.
- According to Fick's law of diffusion (Vgas = A/T × D × ΔP), increasing the surface area (A) directly increases gas flow.
*Incorrect: Deep exhalation*
- **Deep exhalation** would empty the lungs more completely, potentially leading to alveolar collapse in some regions and thus **decreasing the alveolar surface area** available for gas exchange.
- This would also reduce the **driving pressure** for gas diffusion by lowering the alveolar concentration of the inhaled gas.
*Incorrect: Entering a cold chamber*
- Exposure to a **cold chamber** can cause **bronchoconstriction** in some individuals, particularly those with reactive airways, which would increase airway resistance and potentially reduce alveolar ventilation.
- While metabolic rate may slightly increase in the cold, the primary effect on the lungs is unlikely to promote increased gas diffusion in a healthy individual.
*Incorrect: Standing straight*
- **Standing straight** is a normal physiological posture and does not significantly alter the **pulmonary capillary recruitment** or the alveolar surface area in a way that would dramatically increase gas flow compared to a seated position.
- There might be minor gravitational effects on blood flow distribution, but these are generally less impactful than dynamic changes like exercise.
*Incorrect: Assuming a hunched position*
- **Assuming a hunched position** can restrict chest wall expansion and diaphragm movement, leading to **reduced tidal volume** and overall alveolar ventilation.
- This posture, by reducing lung volumes and potentially compressing the lungs, would likely **decrease the effective surface area** for gas exchange and therefore reduce gas flow.
V/Q ratio and gas exchange US Medical PG Question 7: A 19-year-old male soccer player undergoes an exercise tolerance test to measure his maximal oxygen uptake during exercise. Which of the following changes are most likely to occur during exercise?
- A. Increased apical ventilation-perfusion ratio
- B. Decreased physiologic dead space (Correct Answer)
- C. Decreased alveolar-arterial oxygen gradient
- D. Increased arterial partial pressure of oxygen
- E. Increased pulmonary vascular resistance
V/Q ratio and gas exchange Explanation: **Decreased physiologic dead space**
- During exercise, there is improved perfusion to previously underperfused areas of the lung, leading to a **more uniform ventilation-perfusion (V/Q) matching** and thus a decrease in physiologic dead space.
- The increased cardiac output helps to perfuse more capillaries, reducing the amount of ventilated air that does not participate in gas exchange.
*Increased apical ventilation-perfusion ratio*
- At rest, the **apical V/Q ratio is already high** due to gravity-dependent differences in blood flow; exercise partially normalizes these differences.
- While overall V/Q matching improves, the relative V/Q differences between apical and basal regions may become less pronounced, not necessarily a further increase in the apical ratio.
*Decreased alveolar-arterial oxygen gradient*
- During severe exercise, the **A-a gradient often increases slightly** due to increased oxygen diffusion limitations and V/Q mismatch.
- Although overall gas exchange efficiency improves, the sheer volume of oxygen demand can reveal small imbalances, rather than fully eliminating the gradient.
*Increased arterial partial pressure of oxygen*
- Exercise typically leads to **stable or slightly decreased arterial PO2** in healthy individuals due to the increased metabolic demand and potential small V/Q mismatches.
- The body maintains arterial PO2 remarkably well even at high exertion, but it does not usually significantly increase.
*Increased pulmonary vascular resistance*
- During exercise, **pulmonary vascular resistance (PVR) generally decreases** due to recruitment and distension of pulmonary capillaries.
- This decrease in PVR helps to accommodate the increased cardiac output without a significant rise in pulmonary arterial pressure.
V/Q ratio and gas exchange US Medical PG Question 8: A 63-year-old man with alpha-1-antitrypsin deficiency is brought to the emergency department 1 hour after his daughter found him unresponsive. Despite appropriate care, the patient dies. At autopsy, examination of the lungs shows enlargement of the airspaces in the respiratory bronchioles and alveoli. Enzymatic activity of which of the following cells is the most likely cause of these findings?
- A. Alveolar macrophages (Correct Answer)
- B. Ciliated bronchiolar epithelial cells
- C. Elastic fibers in alveolar septa
- D. Type I pneumocytes
- E. Alveolar septal cells
V/Q ratio and gas exchange Explanation: ***Alveolar macrophages***
- In **alpha-1-antitrypsin deficiency**, alveolar macrophages (and neutrophils) release **elastase**, which is normally inhibited by alpha-1-antitrypsin.
- Unchecked elastase activity from alveolar macrophages leads to the **destruction of elastic fibers** in the alveolar walls, causing emphysema with characteristic **panacinar** distribution (worse in lower lobes).
- This results in enlargement of airspaces distal to terminal bronchioles.
*Ciliated bronchiolar epithelial cells*
- These cells are primarily involved in **mucociliary clearance** and do not produce proteolytic enzymes that degrade elastic tissue.
- Their dysfunction would lead to impaired mucus clearance and increased susceptibility to infections, but not emphysema.
*Elastic fibers in alveolar septa*
- Elastic fibers are **extracellular matrix components**, not cells.
- While their destruction is the pathological mechanism of emphysema, they do not have enzymatic activity.
*Type I pneumocytes*
- **Type I pneumocytes** form the structural lining of the alveoli and are primarily involved in gas exchange.
- They do not produce elastase or other proteolytic enzymes responsible for tissue destruction in emphysema.
*Alveolar septal cells*
- This term broadly refers to structural cells including Type I and Type II pneumocytes.
- While these cells may be damaged secondarily in emphysema, they do not produce the elastase responsible for elastic fiber destruction.
V/Q ratio and gas exchange US Medical PG Question 9: A 22-year-old man volunteers for a research study on lung function. He has no history of lung disease or allergies and does not smoke. His pulmonary blood flow is measured in the various labeled segments of the lungs while standing. Then the volunteer, still standing, is given very low continuous positive airway pressure and the blood flow measured again. Which of the following sets of findings are most likely to be present in the second measurements relative to the first?
- A. Increased blood flow in zone 2
- B. Reduced blood flow in zone 3
- C. Reduced blood flow in zone 1
- D. Increased blood flow in zone 3
- E. Increased blood flow in zone 1 (Correct Answer)
V/Q ratio and gas exchange Explanation: ***Increased blood flow in zone 1***
- In healthy standing subjects, **Zone 1** may not exist or is minimal at the apex where alveolar pressure (PA) can exceed arterial pressure (Pa).
- **Very low CPAP** increases alveolar pressure, but when applied at very low levels, it may **recruit collapsed or under-perfused alveoli** by preventing alveolar collapse and improving the pressure gradient.
- The net effect with **very low CPAP** can paradoxically **improve perfusion** in Zone 1 by optimizing alveolar mechanics and reducing vascular resistance through **alveolar recruitment**, particularly in previously under-ventilated apical regions.
*Increased blood flow in zone 2*
- In Zone 2, arterial pressure exceeds alveolar pressure, which exceeds venous pressure (**Pa > PA > Pv**), creating a waterfall effect.
- While CPAP increases alveolar pressure (PA), this would increase the downstream resistance and typically **reduce** the arterial-alveolar pressure gradient (Pa - PA), decreasing flow rather than increasing it.
*Increased blood flow in zone 3*
- **Zone 3** (lung base) normally has the **highest blood flow** where both arterial and venous pressures exceed alveolar pressure (**Pa > Pv > PA**).
- CPAP increases alveolar pressure (PA), which would compress capillaries and **reduce** the pressure gradient, typically decreasing rather than increasing blood flow in this zone.
*Reduced blood flow in zone 1*
- While increasing alveolar pressure with CPAP might be expected to **reduce** Zone 1 perfusion by compressing capillaries, **very low levels of CPAP** can have the opposite effect through **alveolar recruitment** and optimization of lung mechanics.
- The question specifies **very low** CPAP, which is the key—this level improves alveolar patency without significantly compressing capillaries.
*Reduced blood flow in zone 3*
- Zone 3 typically has the highest blood flow due to favorable pressure gradients from gravity.
- CPAP increases PA, which could compress capillaries and reduce the (Pa - PA) gradient, but the **very low level** specified means this effect is minimal and Zone 3 generally maintains adequate perfusion.
V/Q ratio and gas exchange US Medical PG Question 10: A person is exercising strenuously on a treadmill for 1 hour. An arterial blood gas measurement is then taken. Which of the following are the most likely values?
- A. pH 7.56, PaO2 100, PCO2 44, HCO3 38
- B. pH 7.32, PaO2 42, PCO2 50, HCO3 27
- C. pH 7.57 PaO2 100, PCO2 23, HCO3 21 (Correct Answer)
- D. pH 7.38, PaO2 100, PCO2 69 HCO3 42
- E. pH 7.36, PaO2 100, PCO2 40, HCO3 23
V/Q ratio and gas exchange Explanation: ***pH 7.57, PaO2 100, PCO2 23, HCO3 21***
- After 1 hour of strenuous exercise, this represents **respiratory alkalosis with mild metabolic compensation**, which is the expected finding in a healthy individual during sustained vigorous exercise.
- The **low PCO2 (23 mmHg)** reflects appropriate **hyperventilation** in response to increased metabolic demands and lactic acid production. During intense exercise, minute ventilation increases dramatically, often exceeding the rate of CO2 production.
- The **slightly elevated pH (7.57)** and **mildly decreased HCO3 (21 mEq/L)** indicate that respiratory compensation has slightly overshot, creating mild alkalosis, while the bicarbonate is consumed both in buffering lactate and through renal compensation.
- **Normal PaO2 (100 mmHg)** confirms adequate oxygenation maintained by increased ventilation.
*pH 7.36, PaO2 100, PCO2 40, HCO3 23*
- These are **completely normal arterial blood gas values** with no evidence of any physiological stress or compensation.
- After 1 hour of strenuous exercise, we would expect **hyperventilation with decreased PCO2**, not a normal PCO2 of 40 mmHg. This profile would be consistent with rest, not vigorous exercise.
- The absence of any respiratory or metabolic changes makes this inconsistent with the clinical scenario.
*pH 7.56, PaO2 100, PCO2 44, HCO3 38*
- This profile suggests **metabolic alkalosis** (high pH, high HCO3) with inadequate respiratory compensation (normal to slightly elevated PCO2).
- This is **not consistent with strenuous exercise**, which produces metabolic acid (lactate), not metabolic base. The elevated HCO3 suggests vomiting, diuretic use, or other causes of metabolic alkalosis.
*pH 7.32, PaO2 42, PCO2 50, HCO3 27*
- This indicates **respiratory acidosis** (low pH, high PCO2) with **severe hypoxemia** (PaO2 42 mmHg).
- During strenuous exercise, healthy individuals **increase ventilation** to enhance O2 delivery and remove CO2, so both hypoxemia and hypercapnia are unexpected and would suggest severe cardiopulmonary disease or hypoventilation.
*pH 7.38, PaO2 100, PCO2 69, HCO3 42*
- This demonstrates **compensated respiratory acidosis** (normal pH, markedly elevated PCO2 and HCO3).
- The **very high PCO2 (69 mmHg)** indicates severe **hypoventilation**, which is the opposite of what occurs during exercise. This profile suggests chronic respiratory failure with metabolic compensation, such as in severe COPD.
More V/Q ratio and gas exchange US Medical PG questions available in the OnCourse app. Practice MCQs, flashcards, and get detailed explanations.
